Let a be the number of positive multiples of 6 that are less than 30. let b be the number of positive integers that are less than $30$, and a multiple of $3$ and a multiple of $2$. compute $(a - b)^3$.

0 or -3375

Explanation:

The question is somewhat ambiguous because we can't be sure whether B will be positive integers which are multiples of both 3 and 2 or 3 and 2 separately.

For the former:

There a 4 multiples of 6 less than 30: 6, 12, 18, 24.

Positive integers (whole numbers) less than 30: 1-29 ; multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27 and of those, only 6, 12, 18 and 24 are multiples of both 2 and 3.            

Therefore we have (4-4)^3 = 0

For the latter:

multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27 ; Multiples of 2:  2 4 6 8 10 12 14 16 18 20 22 24 26 28 (remove common multiples)

Therefore (4-19)^3 = -3375

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explanation:

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