Compare the path loss in dB for two possible cellular environments where there is (1) free space between mobiles and base stations, and (2) urban area cellular radio with n = 3.1. Use 1.9 GHz at a
distance of 1.5 km and assume isotropic antennas.
Hint: LdB = 20 log(f) + 10n log(d) − 147.56dB

The path loss in between the mobiles base stations, and urban area cellular radio is 136.47 dB

An equation is an expression that shows the relationship between two or more numbers and variables.

Given the equation:

LdB = 20 log(f) + 10n log(d) − 147.56dB

f is the frequency, d is the distance.

Given that f = 1.9 GHz = 1.9 * 10⁹ Hz, d = 1.5 km = 1500 m, n = 3.1. Hence:

L = 20 log(1.9 * 10⁹) + 10(3.1) * log(1500) − 147.56

L = 136.47 dB

The path loss in between the mobiles base stations, and urban area cellular radio is 136.47 dB

Find out more on equation at:

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation: