Engineering, 08.11.2021 09:20 shadow56
A stream of water vapor flowing at a rate of 250 mol/hr is brought from 600°C and 10 bar to 100°C & 1bar.
PART A) Estimate the required cooling rate (kW) using the steam tables.
PART B) Estimate the required cooling rate (kW) using the CP of water vapor.
CP (water vapor) [kJ/mol°C] = 0.03346 + 6.88*10-6T
PART C) What is the physical significance of the difference between the values calculated in Parts A and B?
Answers: 2
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A stream of water vapor flowing at a rate of 250 mol/hr is brought from 600°C and 10 bar to 100°C &a...
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