What is the magnitude of the speed of a person at the equator due to rotational speed
of the earth?

The equatorial diameter of the earth is 12,756 km.

Therefore the equatorial radius is

r = 12756/2 = 6378 km.

The angular velocity of the earth is  

ω = (2π radians)/(24 hours) = 0.2618 rad/h

The tangential velocity of a person at the equator is

v = rω

  = (6378 km)*( 0.2618  rad/h)

  =  1670 km/h

1670 km/h

I hope this helps you.

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import math

x=int(input("enter a number: "))

print (math.sqrt(math.fabs(