A three-phase, 400 V supply is connected to a three-phase star-connected balanced load. The line current is 20 A and the power consumed by the load is 12 kW. Calculate the impedance of the load, phase current, and power factor.

i think its Y connection, voltage applied across each impedance = 400/√3 so phase current = V/Z=400/10√3= 40/√3 amps

Power in each phase = Phase voltage x phase current = 400/√3 x 40/√3 = 1600/3 VA

Total power(three phases) = 1600/3 × 3 =1600 VA or 1.6 kVA

Active power can be calculated if load angle of 10 ohm impedance is known.

Edit: power in each phase is 400/√3 × 40/√3 = 16000/3 VA (it was a calculation mistake in original answer)

So power in all three phases = 16000 VA or 16 kVA not 1.6 kVA as shown in original answer.

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D is the anseer

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