calculate the number of gram of ammonia gas (NH3) contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm

The number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.

Explanation:

Given: Volume = 3.0 L

Temperature = 305 K

Pressure = 1.50 atm

Formula used to calculate the number of moles is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

It is known that moles is the mass of substance divided by its molar mass.

Hence, mass of ammonia gas (molar mass = 17.03 g/mol) is as follows.

Thus, we can conclude that the number of gram of ammonia gas () contained in the a 3.0L vessel at 305 K with a pressure of 1.50 atm is 3.048 g.

answer:

make you upset

explanation:

answer: copyright is extremely important to authors because it constitutes the ownership of one's original work. having ownership means you can protect your work as intellectual property and control who makes money from it—which is you and those to whom you assign rights.