A cylinder of high strength concrete will be compressed until failure. If the compression strength of the concrete is 42 MPa, how much force will need to be applied if the cylinder has a diameter of 120mm

The required force is 475.009 KN

Explanation:

Given the data in the question;

compression strength of the concrete = 42 MPa

diameter of cylinder = 120mm

First we calculate the Area of the cylinder \;

Area of the cylinder A = × D²

we substitute

First we calculate the Area of the cylinder \;

Area of the cylinder A = × (120)²

Area of the cylinder A = × 14400

Area of the cylinder A = 11309.73355 mm²

Now, we know that;

Stress = P / A

P = Stress × A

we substitute

P = 42 × 11309.73355

P = 475008.809 N

P = ( 475008.809  × )KN

P = 475.009 KN

Therefore, The required force is 475.009 KN

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

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