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Engineering, 22.11.2020 21:10 lilyrockstarmag

Octane (C8H18) Is combusted with excess air. The product gas composition is partially known. The dry gas compositions of octane and carbon dioxide are: Octane mole fraction - 0.0062
Carbon dioxide mole fraction - 0.0455
What is the percent excess air fed to the combustor? Assume combustion is complete and use a basis of 100 mol/h of the dry gas (stream 4 below) for your calculations. Note the reaction below is not balanced. Report answer to three sig figs.
n3
yOce
1 Combustor W=
Oc+02 = CO2+W
ni
W = H20
Ốc -CEH18
0.21
0.79
n2
YO2=
yN2=
109
nd-
yoc
yCO2
YO2
YN2

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