Engineering, 12.11.2020 19:10 lizzyhearts
A cylindrical tank, 0.42 m in diameter, drains through a hole in its bottom. At the instant when the water depth is 0.73 m, the flow rate from the tank is observed to be 5 kg/s. Determine the rate of change of water level at this instant.
Answers: 3
(1)
- Current mass of water inside the tank, measured in kilograms.
- Diameter of the cylindrical tank, measured in meters.
- Depth of the water in the tank, measured in meters.
), measured in kilograms per second, by considering geometric characteristics of the cylinder (
) and the fact that water is an incompressible fluid (
):
(2)
is the rate of change of water level, measured in meters per second. 
, 
and 
, then the rate of change of water level is:
![\frac{dh}{dt} = \left[\frac{4}{\pi\cdot \left(1000\,\frac{kg}{m^{3}} \right)\cdot (0.42\,m)^{2}} \right]\cdot (-5\,\frac{kg}{s} )](/tpl/images/0891/7312/4db3a.png)
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A cylindrical tank, 0.42 m in diameter, drains through a hole in its bottom. At the instant when the...
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