Determine the minimum required wire radius assuming a factor of safety of 3 and a yield strength of 1500 MPa.

This question is incomplete, the complete question is;

A large tower is to be supported by a series of steel wires. It is estimated that the load on each wire will be 11,100 N.

Determine the minimum required wire radius assuming a factor of safety of 3 and a yield strength of 1500 MPa.

answer in mm please

the minimum required wire radius is 5.3166 mm

Explanation:

Given that;

Load F = 11100N

N = 3

∝y = 1500 MPa

∝workmg = ∝y / N = 1500 / 3 = 500 MPa

now stress of Wire:

∝w = F/A

500 × 10⁶ = 11100 / A

A = 22.2 × 10⁻⁶ m²

so

(π/4)d² = A

(π/4)d² = 22.2 × 10⁻⁶

d² = 2.8265 × 10⁻⁵

d = 5.3165 7 × 10⁻³ m³

now we convert to mm(millimeters)

d = 5.3166 mm

Therefore the minimum required wire radius is 5.3166 mm

answer:

a

explanation:

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explanation:

r!