A solar-powered steam plant uses a solar collector to heat the water in place of the typical boiler. For a solar-powered steam plant operating on an ideal Rankine cycle, saturated vapor leaves the solar collector at 1 MPa and the pressure in the condenser is 10 kPa. Determine the net work per unit mass and the thermal efficiency of this cycle.

The net work per unit mass  = 692.14 kJ/kg

The thermal efficiency for the cycle =

Explanation:

For an Ideal Rankine cycle:

The following properties were obtained from the steam tables at 1 MPa.

The properties obtained at 10 kPa are:

For 1 - 2 isentropic expansion:

6.585 = 0.6492 + x₂ × 7.4996

6.585 - 0.6492 = 7.4996x₂

5.9358 = 7.4996x₂

x₂ = 5.9358/7.4996

x₂ = 0.791

At 10 kPa;

The pump work for the process:

However, the turbine work can be computed by using the formula:

( 2777.1 - 2083.96 ) kJ/kg

693.14 \ kJ/kg

Thus, the net work can be determined as:

 =

 = 693.14 - 0.9999

 = 692.14 kJ/kg

Similarly, to determine the thermal efficiency of this cycle, we need to first know the heat addition

Finally, the thermal efficiency can be calculated by using the formula:

The thermal efficiency for the cycle =

x+2 because it just doubles hon so the pattern can actually tell you the expression.

so for example,

if x=2 then 2+2 is 4

if x=4 then 4+4 is 8

and so on and so forth.

i really hope that this makes sense and you out in a way hon: )

how is this a question? in order for me to answer it i have to understand the question

explanation: