Given a 250Ω strain gage with a gage factor of 1 which is mounted to a metal bar 0.6m long. The bar is stretched under a tension force and the resistance changes to 251.4 Ω. How much was the bar stretched? _ _mm (Answer in mm to 2 decimal places) What is the length of the bar after it is stretched?

the bar was stretched by

the length of the after it was stretched is

Explanation:

From the information given:

The strain gauge resistance R = 250 Ω

The gauge factor = 1

The original length L = 0.6 m = 600 mm

After the bar is being stretched under tension force;

the new resistance

The gauge factor

where;

  and

ΔR = 251.4 - 250

ΔR = 1.4 Ω

Thus, the length of the after it was stretched is

Thus, the bar was stretched by

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answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)