The diameter of an extruder barrel = 85 mm and its length = 2.00 m. The screw rotates at 55 rev/min, its channel depth = 8.0 mm, and its flight angle = 18°. Head pressure at the die end of the barrel = 10.0(10^6) Pa. Viscosity of the polymer melt = 100 Pa- s
(a) Find the volume flow rate of plastic at the die end of the barrel.
x 10^-6 m^3/s

Qx = 9.10 m³/s  

Explanation:

given data

diameter = 85 mm

length = 2 m

depth = 9mm

N = 60 rev/min

pressure p = 11 × Pa

viscosity n = 100 Pas

angle = 18°

so  Qd will be

Qd = 0.5 × π² ×D²×dc × sinA × cosA   ..............1

put here value and we get

Qd = 0.5 × π² × ( 85 )²× 9    × sin18 × cos18

Qd = 94.305 × m³/s

and

Qb = p × π × D × dc³ × sin²A ÷  12  × n × L    ............2

Qb = 11 × × π × 85  × ( 9   )³ × sin²18 ÷  12  × 100 × 2

Qb = 85.2 × m³/s

so here

volume flow rate Qx = Qd - Qb   ..............3

Qx =  94.305 ×  - 85.2 ×  

Qx = 9.10 m³/s  

answer:

ya

explanation:

sure ill do it