Consider an object consisting of two balls connected by a spring, whose stiffness is460 N/m. The object has been thrown through the air and is rotating and vibrating as it moves. At a particular instant the spring is stretched 0.37 m, and the two balls at the ends of the spring have the following masses and velocities:
⢠1: 8 kg, ⹠4, 11, 0 ⺠m/s

⢠2: 4 kg, â¹ â3, 10, 0 ⺠m/s

(a) For this system, calculate

p with arrowsys = ? kg · m/s

(b) Calculate v with arrowCM ? = m/s

(c) Calculate Ktot ?= J

(d) Calculate Ktrans ? = J

(e) Calculate Krel ? = J

V =  1.6777 m/s , 10.667 , 0 m/s

P = ( 20, 128, 0 ) kg-m/s

= 766 J

=  699.3 J

Krel = 66.7 J

Explanation:

given data

Stiffness K = 460 N/m

Extension e =  0.37 m

solution

we know that here that center of mass is express as

V =       ................1

V1 =  

V1 =  1.6777 m/s

V2 =    

V2 = 10.667 m/s

V3 =    

V3 = 0 m/s

and

P system is

P =

P = (8+4) × ( 1.6777 , 10.667 , 0 )

P = ( 20, 128, 0 ) kg-m/s

and

= K1 + K2

= 0.5 × m × v1² + 0.5 × m × v2²

= 0.5 × 8 ×   + 0.5 × 4 ×  

= 766 J

and

= 0.5 × × ( V(cm)²)

= 0.5 × (8+4) ×

=  699.3 J

and  

Krel = -

Krel = 766 J  - 699.3 J

Krel = 66.7 J

answer:

try looking it up that is always

explanation:

answer:

true

explanation: