1. The equilibrium number of vacancies in Ni at 1123 K is 4.7x1022m-3. The atomic weight and density of Ni at 1123 K are 58.69 g/mol and 8.8 g/cm3. What is the vacancy formation energy of Ni?

vacancy formation energy of Ni is 1.400 eV

Explanation:

given data

number of vacancies in Ni = 4.7 x  

atomic weight = 58.69 g/mol

density = 8.8 g/cm³  

solution

we get here N that is

N  =   ...........1

N =

N =  

and here no of vacancy will be

Nv =  .................2

put here value

take ln both side

Qv = 1.400 eV

so vacancy formation energy of Ni is 1.400 eV

explanation:

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answer:

6.3 is the answer

explanation:

because it is the ex