A sealed, rigid container contains 1 kg of air which is to be treated as an ideal gas. The air is initially at 300 K. Heat is added to the system until air reaches a final temperature of 360 K. Compute the heat transfer for the case of both constant and non-constant specific heat coefficients. Hint: youwill need to apply the firstlawof thermodynamics to find Q.

Constant Specific Heats: , Non-Constant Specific Heats:

Explanation:

By using the First Law of Thermodynamics, it is to notice the inexistence of work interactions due to the rigidness of the container, as well as the absence of mass interactions since it is sealed. In consequence, the equation is simplified to this form:

Below is the summary of calculation for the cases of constant and non-constant specific heats:

Constant Specific Heats

Previous expresion can be re-written to:

Non-Constant Specific Heats

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