A 1-MHz, 40-V peak carrier is modulated by a 5-kHz intelligence signal so that m = 0.7. This AM signal is fed to a 50- antenna. Calculate the power of each spectral component fed to the antenna. (Pc = 16 W, Pusb = Plsb = 1.96 W)

16 W and 1.96 W

Explanation:

The spectral components in the AM wave are unmodulated carrier, USB & LSB.

Total Power of AM antenna = Power in the Unmodulated carrier (Pc) + Power in USB (Pusb) + Power in LSB (Plsb)

Given:

Carrier Frequency Fc=1 MHz,

Voltage of carrier Vc=40 V pk,

Modulated frequency Fm=5 KHz,

Modulation index m=0.7,

Load RL = 50 Ohms

Power in the Unmodulated carrier (Pc) = 16W

Pusb = Plsb = 1.96 W

Pc = Vc(sqr)/RL

= [40V/sqrt 2]/50ohms

Pc=16 W

Since Pusb = Plsb

Plsb = 1/2 × PC (m(sqr)/2)

= 1/2 × 16W × [0.7(sqr)/2]

= 1.96Watts (to confirm that which was already given)

answer:

1.3 + 20

explanation:

20.1.3

answer:

Romans

Explanation:

Hope it helps