MaxCharacter * * a function to compute the 'maximum' character in the list using recursion * You will want to create a helper function to * do the recursion * * precondition: list is not empty * * Examples: * ["ababcdefb"].maxCharacter() == 'f' * ["eezzg"].maxCharacter() == 'z' * ["a"].maxCharacter() == 'a' */

import java.util.Scanner; //to take input from user

public class MaximumCharacter

{

char ch='A';//set initially A which is smallest char

//more than one arguments are required to find max character

char maxCharacter(String line, int len, int counter)

   {

   if(counter==len) //all characters are compared

     return ch;

   else

     {

     if(ch < line.charAt(counter)) //compare ch with each character of input

       {

       ch = line.charAt(counter); //update value of ch

       }

     counter++;//update counter to check next character

     return maxCharacter(line, len, counter); //recursive call with new value of counter

     }

   }

public static void main(String arga[]) //main method to control the program

   {

   MaximumCharacter obj = new MaximumCharacter(); //crating object of class.

   Scanner IN = new Scanner(System.in); //objct of scanner class to take input

   System.out.print(System.lineSeparator() + "Enter a word to find max character: ");

   String input = IN.nextLine(); //take user input

   char c = obj.maxCharacter(input, input.length(),0);   //call function to find max character

   System.out.println("'" + input + "' Max Character = " + c); //print max character

   }

}

Explanation:

x+2 because it just doubles hon so the pattern can actually tell you the expression.

so for example,

if x=2 then 2+2 is 4

if x=4 then 4+4 is 8

and so on and so forth.

i really hope that this makes sense and you out in a way hon: )

sorry what a asnns

explanation: