MIPS Assembly program: Accept N numbers from the user (or list the input array in the program similar to the demo code) and sort the N numbers using any sorting algorithm. Print both the sorted array and unsorted array. N should be greater than or equal to 10.

main:

   la  $t0, Array      # Copy the base address of your array into $t1

   add $t0, $t0, 40    # 4 bytes per int * 10 ints = 40 bytes                              

outterLoop:             # Used to determine when we are done iterating over the Array

   add $t1, $0, $0     # $t1 holds a flag to determine when the list is sorted

   la  $a0, Array      # Set $a0 to the base address of the Array

innerLoop:                  # The inner loop will iterate over the Array checking if a swap is needed

   lw  $t2, 0($a0)         # sets $t0 to the current element in array

   lw  $t3, 4($a0)         # sets $t1 to the next element in array

   slt $t5, $t2, $t3       # $t5 = 1 if $t0 < $t1

   beq $t5, $0, continue   # if $t5 = 1, then swap them

   add $t1, $0, 1          # if we need to swap, we need to check the list again

   sw  $t2, 4($a0)         # store the greater numbers contents in the higher position in array (swap)

   sw  $t3, 0($a0)         # store the lesser numbers contents in the lower position in array (swap)

continue:

   addi $a0, $a0, 4            # advance the array to start at the next location from last time

   bne  $a0, $t0, innerLoop    # If $a0 != the end of Array, jump back to innerLoop

   bne  $t1, $0, outterLoop    # $t1 = 1, another pass is needed, jump back to outterLoop

Explanation:

answer:

d. attempt to find the owner, then leave your information if you cannot find them.

explanation:

d. represents both (b) and (c).

more logical as well.

b and c are to complicated.

glad i could , give me a follow, so if you need with any other question, im here.