A 208 V delta-connected source is energizing two parallel loads. One of the loads is connected in delta and the other in wye. The delta load has impedance ΖΔ-10 L-25°Ω. The wye load has impedance ZY-5 L40°Ω.

Compute the following line current active and reactive power.

Given Information:

Vab = 208 V

ZY = Z1 = 10 < -25°  Ω

Zdelta = Z2 = 5 < 40°  Ω

Required Information:

Line current = Ia = ?

Active Power = P = ?

Reactive Power = Q = ?

° A

Explanation:

First, convert the wye connected load into delta

° Ω

° Ω

Now both of the loads and also the source are delta connected, now we can proceed further.

Find the equivalent load impedance, since the loads are connected in parallel;

Ω

° Ω

The phase current can be found by

A

° A

The relation between phase current and line current is

° A

The Active Power is

The Reactive Power is

answer:

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explanation: