6.6 Parsing strings (Java) (1) Prompt the user for a string that contains two strings separated by a comma. (1 pt) Examples of strings that can be accepted: Jill, Allen Jill , Allen Jill, Allen Ex: Enter input string: Jill, Allen (2) Report an error if the input string does not contain a comma. Continue to prompt until a valid string is entered. Note: If the input contains a comma, then assume that the input also contain

Here is the JAVA code:

import java.util.Scanner;  // to get input from user

public class ParsingStrings //class ParsingStrings

{      public static void main(String[] args) { //start of main() function body

        //  creates object of Scanner class

Scanner scnr = new Scanner(System.in);  

       Scanner inputstream;  // to hold the inputline

       String inputline = ""; //contains the string entered by user

       String substring1 = ""; //First word of the input string

       String substring2 = ""; // next word of the input string after substring1

       System.out.println("Enter input string: ");

//prompts user to enter a string like Allen, Jill

       while (inputline.matches("q") == false) {

//while loop keeps reading the input strings until user enters q to exit

           inputline = scnr.nextLine(); //reads and scans the input string

           inputline = inputline.replaceAll(",",", "); // to replace all commas to " ,"

           inputstream = new Scanner(inputline); //scans input string

           int commaPos = inputline.indexOf(",");

// indexOf() returns the position of comma (",")

//if the string does not have comma and user does not enter q to exit

           if ((commaPos<=-1) && (inputline.matches("q") == false)) {

//display error message as comma is not found in input string

               System.out.println("Error: No comma in string");

               System.out.println("Enter input string: ");            }

//ask user to enter string again until he enters valid comma separated string

//if user enters no string, or one word or no comma seperated 2 words

          else if  ((commaPos <= -1) && (inputline.length() == 0 || inputline.split("\\s+").length < 2) && (inputline.matches("q") == false)) {

//ask user to enter two words

               System.out.println("Please enter two words");

               System.out.println("Enter input string: ");            }

// checks if user has entered q

           else if (inputline.matches("q") == false) {

               substring1 = inputstream.next(); //stores word 1

               substring2 = inputstream.nextLine(); //stores word 2

//prints the first word by replacing empty spaces with comma

               System.out.println("First word: " + substring1.replaceAll("\\s",""));

//prints second word by removing empty spaces

               System.out.println("Second word: " + substring2.replaceAll("\\s","").replaceAll("\\W",""));

               System.out.println("\n");

// asks user to enter string until user types q

               System.out.println("Enter input string: ");           }        }    } }

Explanation:

The program is briefly explained in the comments given in the code.

The program takes input from user in the form of strings.

The string contains two sub strings separated by comma.

commaPos stores the position of comma in the input string using indexOf() function.

If and else if conditions used here checks the input string for the following:

The screenshot of output of the program is attached.

angvrswer:

vfg

grfhrtrhr:

j

h

j

jjj

jj

j

j

j

m

j

h

yjujuju

jujuhuyhyt

j

hy

h

gh

g

g

g

g

gg

t

gt

gt

g

g

g

g

g

ef

f

d

dd

d

d

dd

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

f

s

bv

fb

c

fd

f

bf

bgf

n

g

bgr

gbr

bgr

gtr

bgr

gb

gb

gbgbbg

b

bgg

bbg

bfg

s

dcwf

fdb

b

ggb

bg

b

d

fh

d

e

f

w

fh

cd

cr

r

h

f

ww

a

v

f

vf

tr

rfe

rr

g

gg

e

go

d

d

c

r

rv

ng

gtg

gegte

g

gf

gf

g

gff

gf

gf

g

g

g

f

ds

wd

dfg

h

gfdsax

cvfbgnh

jmhngf

dsaazxscvb

nmhgb

fvdcsxaz

zxcv

bghn

fd

gb

h

answer:

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