A reversible power cycle whose thermal efficiency is 40% receives 50 kJ by heat transfer from a hot reservoir at 600 K and rejects energy by heat transfer to a cold reservoir at temperature TC.
1. Determine the energy rejected, in kJ, and TC, in K.

Explanation:

For this question, we take into consideration, the following:

We calculate the efficiency of the cycle using the following equation:

where is the temperature of the cold reservoir and is the temperature of the hot reservoir.

To calculate, , we rearrange the above equation.

⇒ 600 ( 1 - 0.4 )

⇒ 600 × 0.6

⇒ 360 K

The efficiency of the cycle is then calculated using the following equation:

Using this equation, we find the amount of heat added to the cold reservoir:

⇒ 50 ( 1 - 0.4)

⇒ 50 × 0.6

⇒ 30 KJ

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation: