Engineering, 20.02.2020 08:35 kevonmajor

2.18 LAB: Warm up: Variables, input, and type conversion (1) Prompt the user to input an integer between 32 and 126, a float, a character, and a string, storing each into separate variables. Then, output those four values on a single line separated by a space. (Submit for 2 points).

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Answer from: truesarah111

The solution code is written in Java.

import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Enter an integer between 32 - 126: "); int data1 = input.nextInt(); System.out.print("Enter a floating point number: "); double data2 = input.nextDouble(); System.out.print("Enter a character: "); char data3 = input.next().charAt(0); input.nextLine(); System.out.print("Enter a string: "); String data4 = input.nextLine(); System.out.println(data1 + " " + data2 + " " + data3 + " " + data4); } }

Explanation:

Since we need user input, we create a Scanner object (Line 7). Then we can start using the Scanner object to prompt user to input the integer, float, character and string (Line 8 - 20). Please note that we have to use four different input methods, nextInt(), nextDouble(), next().charAt(0) and nextLine(), to get the user input with four different data types and store them into their respective variables.

We can use println() method to print the four values in one line (Line 22) through string concatenation. Whenever a value is joined with a string (e.g. a single space " ") using the + operator, the value will be converted to string regardless its original type is integer, float or character.

Answer from: Quest

how is this a question? in order for me to answer it i have to understand the question

explanation:

Answer from: Quest

answer:

d. attempt to find the owner, then leave your information if you cannot find them.

explanation:

d. represents both (b) and (c).

more logical as well.

b and c are to complicated.

glad i could , give me a follow, so if you need with any other question, im here.

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