Amysterious device found in a forgotten laboratory accumulates charge at a rate specified by the expression gm = 9 - 10tc from the moment it is switched on. (a) calculate the total charge contained in the device at t: o. (b) calculate the totalcharge contained at t: 1 s. (c) determine the current flowing into the device at t: 1 s, 3 s, and 10 s.

9C

-1C

I (1) = I (3) = I(10) = -10 Amps

Explanation:

Given expression : q(t) = 9 - 10*t

a) @ t = 0, q(0) ?

q (0) = 9 - 10 * 0 = 9 C

Answer : 9C

b) @ t = 1, q(1) ?

q (1) = 9 - 10 * 1 = 1 C

Answer : 1C

c) t = 1 , 3 , 10 s what is I (1) , I (3), I (10) ?

I = dq / dt

I = dq/dt = -10 Amps

Hence,

I (1) = I (3) = I(10) = -10 Amps

Answer : I (1) = I (3) = I(10) = -10 Amps

answer:

d. attempt to find the owner, then leave your information if you cannot find them.

explanation:

d. represents both (b) and (c).

more logical as well.

b and c are to complicated.

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answer:

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