Determine the tension developed in cord de required for equilibrium of the lamp. express your answer to three significant figures and include the appropriate units.

Fde = 1080 N (3 sig fig)

Explanation:

Taking point E

Sum of forces at E in x direction:

Fde cos (30) - Fcd = 0   Eq 1

Sum of forces at E in y direction:

Fde sin (30) - Wf = 0   Eq 2

Wf = m*g = 55 * 9.81 = 539.55 N

Using Eq 2 to evaluate Fde

Fde = Wf / sin (30) = 539.55 / sin (30) = 1079.1 N

Fde = 1080 N (3 sig fig)

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explanation:

answer:

an example of solubility is salt or sugar dissolving in water.

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