If the electric field just outside a thin conducting sheet is equal to 1.5 n/c, determine the surface charge density on the conductor.

The surface charge density on the conductor is found to be 26.55 x 1-6-12 C/m²

Explanation:

The electric field intensity due to a thin conducting sheet is given by the following formula:

Electric Field Intensity = (Surface Charge Density)/2(Permittivity of free space)

From this formula:

Surface Charge Density = 2(Electric Field Intensity)(Permittivity of free space)

We have the following data:

Electric Field Intensity = 1.5 N/C

Permittivity of free space = 8.85 x 10^-12 C²/N.m²

Therefore,

Surface Charge Density = 2(1.5 N/C)(8.85 x 10^-12 C²/Nm²)

Surface Charge Density = 26.55 x 10^-12 C/m²

Hence, the surface charge density on the conducting thin sheet will be 26.55 x 10^ -12 C/m².

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answer:

an example of solubility is salt or sugar dissolving in water.

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