The truck travels in a circular path having a radius of 50 m at a speed of v = 4 m> s. for a short distance from s = 0, its speed is increased by v # = (0.05s) m> s 2, where s is in meters. determine its speed and the magnitude of its acceleration when it has moved s = 10 m.

Magnitude of velocity when s is 10 m= 4.58m/s

Magnitude of acceleration when s is 10 m = 0.653 m/s²

Explanation:

Radius of circular path = 50m

Speed = 4m/s

increase in acceleration = (0.05s)m/s²

speed and acceleration when s is 10 m = ?

Magnitude of Velocity:

From third equation of motion

Magnitude of Acceleration:

The tangential component of acceleration is

The normal component of acceleration is

Substituting tangential and normal component in (1)

a=0.653 m/s²

answer:

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