The fatigue data for a brass alloy are given as follows: stress amplitude (mpa) cycles to failure 170 3.7 × 104 148 1.0 × 105 130 3.0 × 105 114 1.0 × 106 92 1.0 × 107 80 1.0 × 108 74 1.0 × 109 (a) make an s–n plot (stress amplitude vs logarithm of cycles to failure) using these data. (b) determine the fatigue strength at 4 × 106 cycles. (c) determine the fatigue life for 120 mpa.

answer:

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answer: report them

explanation:

answer:

Explanation:

i hope dis helps

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)