Assume the gasoline is burned with 99% efficiency in a car engine, with 1% remaining unburned in the exhaust gases as vocs (volatile organic compounds). if the engine exhausts 16 kg of gases (mw=30) for each kg of gasoline (mw=100), calculate the fraction of vocs in the exhaust. give your answer in parts per million

187ppm.

Explanation:

To develop the problem we first need to perform mass conversions to moles. In this way for gases your conversion is given by,

For the VOC's same:

then,

We only need to obtain the fraction of Voc's in exhaust. This will be in particles per million, so

answer:

sure does

explanation:

answer: chicken nuggets.

explanation: