Agas is compressed in a piston-cylinder assembly from p1= 2 bar to p2= 8 bar, v2= 0.02 m^3 in a process during which the relation between pressure and volume is pv^1.3= constant. the mass of the gas is 0.2 kg. if the specific internal energy of the gas increases by 50 kj/kg during the process, determine the heat transfer, in kj. kinetic and potential energies are negligible.

heat transfer is 4.6067 kJ

Explanation:

given data

P1= 2 bar = 2 × N/m²

P2= 8 bar = 8 × N/m²

V2= 0.02 m³

m = 0.2 kg

= constant

V(1 to 2) = 50 kJ/kg

U(1 to 2)  = m V(1 to 2) = 0.2 × 50 = 10 kJ

solution

v1 = 0.05809 m³

and

by 1st law of thermodynamics for closed system is

Q - W = ΔU

so  calculate the work expansion that is

W =

W =  

W = -14.6067 kJ

so heat transfer from 1st law of thermodynamic is

Q = U + W

Q = 10 + ( - 14.06067 )

Q = -4.6067kJ

so

heat transfer is 4.6067 kJ

answer:

i dont know the answer but good luck

explanation:

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