Abasketball is filled with atmospheric air. what percent of air mass of the same temperature must be added to the ball to increase the air pressure by 20 % if the volume increases by 5% at the same time?

26 % of mass is added.

Explanation:

We know that

P V = m R T            1

P=Pressure

V=Volume

R= Gas constant

T= Temperature

m=Mass

Lets mass added =m'

P'=1.2 P

V'=1.05 V

P' V' = m' R T          

1.26  P V = m' R T                                 2

Form equation 1 and 2

1.26 = m' /m

m' = 1.26 m

Mass added = m' - m

                 Δ m   = 1.26 m - m = 0.26 m

So percentage of mass added  =   Δ m /m

                                                    =0.26

We can say that 26 % of mass is added.

sorry what a asnns

explanation: