Air is compressed in a reversible, isothermal, steady- flow process from 15 psia, 100°f to 100 psia. calculate the work of compression per pound, the change of entropy, and the heat transfer per pound of air compressed.

|W|=169.28 KJ/kg

ΔS = -0.544 KJ/Kg.K

Explanation:

Given that

T= 100°F

We know that

1 °F = 255.92 K

100°F = 310 .92 K

We know that work for isothermal process  

Lets take mass is 1 kg.

So work per unit mass

We know that for air R=0.287KJ/kg.K

W= - 169.28 KJ/kg

Negative sign indicates compression

|W|=169.28 KJ/kg

We know that change in entropy at constant volume

ΔS = -0.544 KJ/Kg.K

x+2 because it just doubles hon so the pattern can actually tell you the expression.

so for example,

if x=2 then 2+2 is 4

if x=4 then 4+4 is 8

and so on and so forth.

i really hope that this makes sense and you out in a way hon: )

can you make it more obvious. i can't see it properly