The ultimate tensile strength (stress) for steel is 100 n/m^2 and for an aluminum alloy it is 70 n/m^2. what is the ultimate tensile strength for steel and aluminum in lb/in. and kip/in^2?

The ultimate tensile strength for steel is 0.145lb/in^2 and 1.45×10^-4 kip/in^2.

And fot aluminum is 0.0101lb/in^2 and 1.017×10^-5 kip/in^2.

Explanation:

First we are going to calculate the tensile strength for steel.

 The exercise says that the tensile strength for steel is 100 N/m^2. To express this numer in lb/in^2, we using a convertion char. According to the chart we can say : 1lb= 4.44 N and 1 in = 0.0254 m.

 So using multiplication and divisions ⇒ = 0.145 lb/in^2.

Using again the converstion chart we deduce that 1 kip= 1000lb. So we have to divide the 0.145lb/in^2 with 1000lb to express this numer in kip/in^2.

   ⇒ = 1.45×10^-4 kip/in^2.

To conclude, 100N/m^2 = 0.145lb/in^2 = 1.45×10^-4 kip/in^2.

Now for the aluminum we use the same convertions to express 70N/m^2 in lb/in^2.

⇒= 0.0101 lb/in^2.

and to express this in kip/in^2 :

      ⇒ 0.0101lb/in^2 * 1kip/1000lb= 1.017×10^-5 kip/in^2.

In conclusion, 70N/m^2 = 0.0101lb/in^2 = 1.017×10^-5 kip/in^2.

import math

x=int(input("enter a number: "))

print (math.sqrt(math.fabs(