What is the thermal energy contained within a cubic kilometre of granite (in barrels of oil equivalent) for every one degree change in temperature? use the following parameters in your calculation: specific heat of granite = 790 (j/kgc) density of granite = 2700 kg/m3 energy in 1 barrel of oil = 6.118e9 j

348643.34 barrels of oil

Explanation:

Given;

Volume of the granite = 1 km³ = 1000³ m³

Specific heat of granite, C = 790 J/kg.°C

Density of granite = 2700 kg/m³

Energy in 1 barrel of oil = 6.118 × 10⁹ J

For every 1° change in temperature, ΔT = 1°C

Now,

The thermal energy stored is given as;

Thermal energy = mCΔT

where, m is the mass

the mass of 1 km³ of granite = Density × Volume

or

the mass of 1 km³ of granite = 2700 × 1000³ = 27 × 10¹¹ Kg

therefore,

Thermal energy = 27 × 10¹¹ × 790 × 1

or

Thermal energy = 21330 × 10¹¹ J

hence,

the thermal energy in terms of barrels of oil

= Total thermal energy / Energy stored in 1 barrel of oil

= 21330 × 10¹¹ J / ( 6.118 × 10⁹ J per barrel )

= 348643.34 barrels of oil

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