Prove that the slope of a constant-volume line is steeper than that for a constant-pressure line for a given state (point) on the t-s diagram.

Explanation:

We know that first T-ds equation

 Tds=dT+Pdv

For constant volume process dv=0

⇒Tds=dT

So          ----(1)

We know that second T-ds equation

 Tds=dT-vdP

For constant pressure process dP=0

⇒Tds=dT

So             ---(2)

We know that is always greater than .

So from equation (1) and (2) we can say that slope of constant volume process will be always greater than constant pressure process on T-s diagram.

answer: 500 wph.

explanation: