Alight pressure vessel is made of 2024-t3 aluminum alloy tubing with suitable end closures. this cylinder has a 90mm od, a 1.65mm wall thickness, and poisson's ratio 0.334. the purchase order specifies a minimum yield strength pf 320 mpa. what is the factor of safety if the pressure-release valve is set at 3.5 mpa?

Given:

Outer Diameter, OD = 90 mm

thickness, t = 0.1656 mm

Poisson's ratio, = 0.334

Strength = 320 MPa

Pressure, P =3.5 MPa

Formula Used:

1).   =

2). factor of safety, m =

Explanation:

Now, for Inner Diameter of cylinder, ID = OD - 2t

ID = 90 - 2(1.65) = 86.7 mm

Outer radius,   = 45mm

Inner radius,   = 43.35 mm

Now by using the given formula (1)

  =

  = =93.74 MPa

Now, Using formula (2)

factor of safety, m = \frac{320}{93.74} = 3.414

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)