The gas expanding in the combustion space of a reciprocating engine has an initial pressure of 5 mpa and an initial temperature of 1623°c. the initial volume is 0.05 m^3 and the gas expands through a volume ratio of 20 according to the law pv^1.25 = constant. calculate: a) work transfer b) heat transfer

a). Work transfer = 527.2 kJ

b). Heat Transfer = 197.7 kJ

Explanation:

Given:

= 5 Mpa

= 1623°C

                       = 1896 K

= 0.05

Also given

Therefore, = 1  

R = 0.27 kJ / kg-K

= 0.8 kJ / kg-K

Also given :

   Therefore, =

                      = 0.1182 MPa

a). Work transfer, δW =

                              = 527200 J

                             = 527.200 kJ

b). From 1st law of thermodynamics,

Heat transfer, δQ = ΔU+δW

   =

  =

  =

  = 197.7 kJ

answer:

2d

explanation: