Moist air (dry air and water vapor) at a state of 18 °c dry bulb, 15 °c chamber and for each kilogram of dry air passing through the chamber, 0.001 kg of liquid water at 100 °c is injected and totally evaporated. estimate the moisture content, ω and enthalpy and dry bulb temperature of the moist air leaving the wet bulb at 101 kpa, enters a chamber.

answer:

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explanation:

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answer:

the formula for amps is watts divided by volts. to use the chart, cover up the a with your finger and use the remaining chart calculation of w divided by v. using our sample panel data, 60 watts divided by 12 volts equals 5 amps.

explanation:

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