Design a solid steel shaft to transmit 14 hp at a speed of 2400rpm f the allowable shearing stress is given as 3.5 ksi.

 Is required a 0.8 inches diameter steel shaft.

Explanation:

With the power P and the rotating speed n (RPM), we can find the torque applied:

T = P/N

Before calculating the torque, we convert the power and rotating speed units:

Replacing the values, the torque obtained is:

Then the maximum shearing stress will be located at the edge of the shat at the Maximus radius:

Here J is the moment of inertia and R a radius. For a solid shaft, it is calculated by:

Where D is shaft's diameter. Replacing the expression of J in

As the radius is half of the diameter:

For the maximum stress of 3.5 ksi (3500 psi = 3500\ lb/in^2) and the calculated torque:

Solving for D:

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation: