Assume that x and y are boolean vairables and have been properly initialized (x && y ) && !(x || y)

Valye of (x && y) can be true or false.
if (x && y) is true then !(x && y) is false. Which makes given statement (x && y) || !(x && y) = true.
if (x && y) is false then !(x && y) is true. Which makes given statement (x && y) || !(x && y) = true.
Hence value of given boolean statement is always true.

So option A is correct.

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