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Computers and Technology, 22.06.2019 22:30

Alex’s family members live in different parts of the world. they would like to discuss the wedding plans of one of their distant relatives. however, alex wants all the family members to talk to each other simultaneously so that they can make decisions quickly. which mode of internet communication should they use? a. blog b. email c. wiki d. message board e. instant messaging

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Computers and Technology, 23.06.2019 09:00

Which company provides a crowdsourcing platform for corporate research and development? a: mtruk b: wiki answers c: mediawiki d: innocentive

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Computers and Technology, 23.06.2019 09:30

:you areto design the controller for alight that functions both as an ordinary light and also as a motion activated light and alarm. a.if the manual switch s is on, then the light l is on. b.besides the manual switch, there is a motion detector, m1, which activatesthis light.c.if motion is detected but the light is on anyway because s is on, only then a secondoutput a, an alarm, is turned on. d.the disable switch, d, disables the motion activated light and alarmbut leaves manual control operation of the light using switch s.(i)read the problem statement and clearly identify the inputs and outputs for the circuit you are designing. (ii)create the truth table for this system; include the light, alarm, switch, disable, and the motion sensor.(iii)draw a schematic of this system.

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Computers and Technology, 24.06.2019 11:20

Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput.find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }

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