The code to perform a binary search is below. Match the variable name with what it holds. first = 0
last = len(data) - 1
done = False
numberPasses = 0 while first <= last and not done:
middle = (first + last) // 2
numberPasses =
numberPasses + 1
if data[middle] == 10:
done = True
else:
if data[middle] > 10:
last = middle - 1
else:
first = middle + 1

(This is a matching thing, the last, middle, and first will be matched with the options below:)

-the index of the center item in the list being considered
-the index of the rightmost member of the list being considered
-the index of the leftmost member of the list being considered

Answer(d) readers name,your name,the date,the subject,and the body of the memo;

Answertrue

Public static int mystery(int a[], int x) {     int c = 0;     for(int i = 0; i < a.length; i++) {        if (a[i] == x) c++;     } return c; }the method counts how many times an integer shows up in an integer array.the c variable is declared in the method to keep track of how many times the certain value has shown up.the for-loop loops through the entire array.the line    if (a[i] == x) c++;   checks if each element of the array is equal to the inputted integer to check. for each number in the array that is equal to the inputted integer x, the c variable will be incremented by 1. otherwise it will do nothing.then c is returned at the end of the loop.for example, if we have, in the main method with the mystery method coded in the class:     int arraytest[] = {2, 23, 23, 23, 3};     int testme = 23;     int count = mystery(arraytest, testme);     system.out.println(count); then the print out will be    3 because there are three 23s in that array.

Snapccchatt is not secure, if you send a picture on snapp chatt someone can extract the geo ttag and get your geo ddata and find out like they would have your ip your address or your or current location.