Write a program which will create an array of size 10. Fill the array with random numbers from 0 - 100. (use a loop and random number generator rand) Once you are done with this, you will then write a loop which will go through each element of the array, display the contents of that element and tell if that element is an even number or odd number. Go through all the elements again and this time tell me how many are even and odd.

Explanation:

The following code is written in Java. It randomly generates 10 integers and adds them to an integer array called myArr. Then it loops through the array calculating if each number is even or odd. If it is even it adds 1 to the evenCount variable and prints out the number saying that it is even. Otherwise it adds 1 to the oddCount variable and prints the number saying that it is odd. The program was tested and the output can be seen in the attached image below.

import java.util.*;

class {

   // Main Method

   public static void main(String[] args) {

       Random rand = new Random();

       int[] myArr = new int[10];

       for (int i = 0; i<10; i++) {

           int n = rand.nextInt(101);

           myArr[i] = n;

       }

       int evenCount = 0;

       int oddCount = 0;

       for (int x : myArr) {

           if ((x % 2) == 0) {

               evenCount += 1;

               System.out.println(x + " is Even");

           } else {

               oddCount +=1;

               System.out.println(x + " is Odd");

           }

       }

       System.out.println("The Array has a total: ");

       System.out.println(evenCount + " Even Numbers");

       System.out.println(oddCount + " Odd Numbers");

   }

}

answeroverload;