What will be the pseudo code for this

Now, it has been a while since I have written any sort of pseudocode. So please take this answer with a grain of salt. Essentially pseudocode is a methodology used by programmers to represent the implementation of an algorithm.

create a variable(userInput) that stores the input value.

create a variable(celsius) that takes userInput and applies the Fahrenheit to Celsius formula to it

Fahrenheit to Celsius algorithm is (userInput - 32) * (5/9)

Actual python code:

def main():

   userInput = int(input("Fahrenheit to Celsius: "))

   celsius = (userInput - 32) * (5/9)

   print(str(celsius))

main()

Explanation:

I hope this helped :) If it didn't tell me what went wrong so I can make sure not to make that mistake again on any question.    

a.s= 230t– 110; 1500 lbc.t= 230s– 110; 1500 lbb.s= 230t+ 110; 1720 lbd.s= 199t– 110; 1280 lb