A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. Assuming that the weights are normally distributed, what is the weight that represents the 75th percentile?​

5.0674

Explanation:

Given that :

Mean, μ = 5 pounds

Standard deviation, σ = 0.1

Given that weight are normally distributed ;

From the Z table, the Zscore or value for 75th percentile weight is :

P(Z < z) = 0.75

z = 0.674

Using the relation :

Zscore = (x - μ) / σ

x = weight

0.674 = (x - 5) / 0.1

0.674 * 0.1 = x - 5

0.0674 = x - 5

0.0674 + 5 = x - 5 + 5

5.0674 = x

The weight which corresponds to the 75th percentile is 5.0674

make sure each item is its own paragraph.

the answer to your question would be something called hertz. the unit of measurement called a hertz, which is one cycle per second, is used to measure clock speed. within one cycle, your computer processes, refreshes, or updates itself to the changes that it is going through. in the case of computer clock speed, one hertz equals one tick per second. the clock speed of computers is usually measured in megahertz (mhz) or gigahertz (ghz)