Computers and Technology, 16.06.2021 18:20 Celsie
Given the following: int num1 = 5; //addressed at 1877112 int num2 = 15; //addressed at 1877300 int num3 = 20; //addressed at 1877192 double d1 = 1.05; //addressed at 1374376 double d2 = 2.25; //addressed at 1374360 double d3 = 3.14; //addressed at 1374344 After these statements: double* ptr1 = &d2; ptr1 = ptr1 - 2; What will be the address contained in ptr1?
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Given the following: int num1 = 5; //addressed at 1877112 int num2 = 15; //addressed at 1877300 int...
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