Assume that a, b, and c have been declared and initialized with int values. The expression !(a > b || b <= c)
is equivalent to which of the following?

a. a > b && b <= c
b. a <= b || b > c
c. a <= b && b > c
d. a < b || b >= c
e. a < b && b >= c

Option c (a <= b && b > c) and Option e (a < b && b >= c) is the correct answer.

Explanation:

According to the question, the given expression is:

⇒ !(a > b || b <= c)

There will be some changes occur between the values such as:

So that the expression will be:

⇒ a <= b && b > c

and

⇒ a < b && b >= c

Other choices are not connected to the expression or the rules. So the above two alternatives are the correct ones.

you have to first get good enough where you are an ace or master, then some of the creators could make you a mod. (this is pretty hard to do though)

idk

sorry.

but i may be able to identify that is not you < 3