With the code int foobar(int*n){*n=*n+1; return*n;} when called int k=6; printf("k=%d\n",k)
what get printed? *
foobar (k)=6,*foobar (k)=7,k=*foobar (k)=6, k=7​

Your program will make use of long long int variables for all calculations. note: the use of long long int requires that you have c++11 support. you should have this automatically if you are using a newer version of visual studio. the support is there for gcc as well, but you may need the -std=c++11 or -std=c++0x compiler flag. you first need to read in the total number of seconds. there is no prompt for the read (that is, you just do the cin without using a cout to display a prompt). this is going to seem a little strange when you are running your program in your ide

What is the total resistance in a circuit that contains three 60 ohm resistors connected in a series? a. 20 ohms b. 120 ohms c. 60 ohms d. 180 ohms

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