Write a function that displays the character that appears most frequently in the string. If several characters have the same highest frequency, displays the first character with that frequency. Note that you must use dictionary to count the frequency of each letter in the input string. NO credit will be given without using dictionary in your program

The function is as follows:

def getMode(str):

occurrence = [0] * 256

dict = {}

for i in str:

 occurrence[ord(i)]+=1;

 dict[i] = occurrence[ord(i)]

highest = max(dict, key=dict.get)

print(highest)

Explanation:

This defines the function

def getMode(str):

This initializes the occurrence list to 0

occurrence = [0] * 256

This creates an empty dictionary

dict = {}

This iterates through the input string

for i in str:

This counts the occurrence of each string

 occurrence[ord(i)]+=1;

The string and its occurrence are then appended to the dictionary

 dict[i] = occurrence[ord(i)]

This gets the key with the highest value (i.e. the mode)

highest = max(dict, key=dict.get)

This prints the key

print(highest)

the supreme court is the highest of courts so this would be true

have a great day!

the formula for work is

f*d

therefore work=2.0n*3.0=6n*m