Suppose that a disk drive has 5,000 cylinders, numbered 0 to 4,999. The drive is currently serving a request at cylinder 2,150, and the previous request was at cylinder 1,805. The queue of pending requests, in FIFO order, is:

The queue pending requests of FIFO order is ;

86, 1470, 1774, 948, 1509, 1022, 1750, 130.

Explanation:

The FCFS schedule is 143, 86, 1470, 913, 1774, 948, 1509, 1022, 1750, 130.

Total seek distance is 7081.

The SSTF schedule is 143, 130, 86, 913, 948, 1022, 1470, 1509, 1750, 1774.

Total seek distance is 1745.

The LOOK schedule is 143, 913, 948, 1022, 1470, 1509, 1750, 1774, 130, 86.

Total seek distance is 3319.

The SCAN schedule is 143, 913, 948, 1022, 1470, 1509, 1750, 1774, 4999, 130, 86.

Total seek distance is 9769.

answer: internal fragmentation is the difference between the (fixed) size of a memory hole and the data within in that memory. for example, if a 1,024 byte block of memory holds 800 bytes of data, then the 224 bytes difference is considered lost to internal fragmentation.

external fragmentation occurs when the sum of memory fragments is large enough to satisfy a request, but the holes are non-contiguous and the request cannot be satisfied. this can occur when memory is dynamically allocated and freed.

explanation:

you paid for the subscription lol